(-9.8/2)t^2+500t+15=0

Solution for (-9.8/2)t^2+500t+15=0 equation:

(-9.8/2)t^2+500t+15=0


Domain of the equation: 2)t^2!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

500t+(-9.8/2)t^2+15=0

We multiply all the terms by the denominator


500t*2)t^2+(+15*2)t^2-9.8=0

We add all the numbers together, and all the variables

500t*2)t^2+30t^2-9.8=0

Wy multiply elements

1000t^2=0

a = 1000; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1000·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{2000}=0$